Correct expression for density of an ideal gas mixture of two gases 1 and 2, where $m_{1}$ and $m_{2}$ are masses and $n_{1}$ and $n_{2}$ are moles and $M_{1}$ and $M_{2}$ are molar masses.

d = \frac{(m_{1} + m_{2})}{(M_{1} + M_{2})}

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d = \frac{(m_{1} + m_{2})}{(n_{1} + n_{2})} \frac{P}{R T}

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d = \frac{(n_{1} + n_{2})}{(m_{1} + m_{2})} \times \frac{P}{R T}

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Solution

The correct option is C $d = \frac{(m_{1} + m_{2})}{(n_{1} + n_{2})} \frac{P}{R T}$
By ideal gas equation $P V = n R T; d = (P / R T) \times 1 / M$
So for a mixture of two gases,
$d = \frac{(m_{1} + m_{2})}{(n_{1} + n_{2})} \frac{P}{R T}$

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Similar questions

If two lines have direction cosines

$l_{1}, m_{1}, n_{1}$ and $l_{2}, m_{2}, n_{2}$

then the condition for these lines being perpendicular to each other would be -

(l_{1}, m_{1}, n_{1})

(l_{2}, m_{2}, n_{2})

\frac{l_{1}}{l_{2}} = \frac{m_{1}}{m_{2}} = \frac{n_{1}}{n_{2}}

l_{1}, m_{1}, n_{1}

l_{2}, m_{2}, n_{2}

l_{1}, m_{1}, n_{1}

l_{2}, m_{2}, n_{2}

lf $θ$ is the angle between two lines whose d.cs are $l_{1}, m_{1}, n_{1}$ and $l_{2}, m_{2}, n_{2}$ , then

$\frac{Σ (l_{1} + l_{2})^{2}}{4 {cos}^{2} (\frac{θ}{2})} + \frac{Σ (l_{I} - l_{2})^{2}}{4 {sin}^{2} (\frac{θ}{2})} =$

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