Correct expression for water potential of plasmolysed cell will be

ψ_{w} = ψ_{s}

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ψ_{s} = ψ_{p}

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ψ_{w} = 0

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ψ_{w} = ψ_{s} + (- ψ_{p})

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Solution

The correct option is A $ψ_{w} = ψ_{s}$
Free energy is potential to do work and the free energy of water is ‘water potential' ( $ψ_{w})$ .
$ψ_{w} = ψ_{s} + ψ_{p}$ , where
$ψ_{s}$ = solute potential
$ψ_{p}$ = pressure potential
A plasmolysed cell is flaccid and the turgor pressure (pressure potential) of such a cell is zero.
$∴ ψ_{w} = ψ_{s}$

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