Correct formula of the complex formed in the brown ring test for nitrates is ___________.

F e S O_{4} N O

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[F e (H_{2} O)_{5} N O]^{2 +}

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[F e (H_{2} O)_{5} N O]^{+}

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[F e (H_{2} O)_{5} N O]^{3 +}

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Solution

The correct option is C $[F e (H_{2} O)_{5} N O]^{2 +}$
The correct formula of the complex formed in the brown ring test for nitrates is: $[F e (H_{2} O)_{5} N O]^{2 +}$
It is formed through the following reaction:
$F e S O_{4} + 5 H_{2} O + N O \to [F e (H_{2} O)_{5} N O] S O_{4}$

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[F e (H_{2} O)_{5} N O]^{2 +}

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[F e (H_{2} O)_{5} N O]^{2 +}

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[F e (H_{2} O)_{5} N O]^{2 +}

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c o n c . H_{2} S O_{4}

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