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Saturated and Unsaturated Hydrocarbons

Correct order...

Question

Correct order at C-H bond dissociation energy of following compound:-
(I) $C H_{3} - H$
(II) $C H_{3} - C H_{2} - H$
(III) $C H_{3} = C H - C H_{2} - H$
(IV) $C_{6} H_{5} - H$

I > II > III > IV

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IV > III > II > I

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IV > I > II > III

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II > I > VI > III

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Solution

The correct option is C IV > I > II > III
$C_{6} H_{5} - H > C H_{3} - H > C H_{3} - C H_{2} - H > C H_{3} = C H - C H_{2} - H$
The correct order is $I V > I > I I > I I I$ .

Suggest Corrections

Similar questions

C H_{3} - H I C H_{3} C H_{2} - H I I; C H_{2} = C H - C H_{2} - H I I I C_{6} H_{5} - H I V

(i) C H_{3} - + C H - C H_{2} - O C H_{3}

(i i) C H_{3} - + C H - C H_{2} - C H_{3}

(i i i) C H_{3} - + C H - O | | C - C H_{3}

What are the hybridization states of each carbon atom(s) in the following molecules ?

(i) $C H_{3} * C H_{2} C H_{2} C H_{3}$

(ii) $C H_{2} = C^{*} H - C H = C H_{2}$

(iii) $C H_{3} * C H = C H - C H_{3}$

(iv) $H - * C \equiv C - H$

H - X

C H_{2} = C H - O H

C H_{2} = C H - C H_{2} O H

C H_{3} - C H_{2} - O H

C H_{3} - C H | O H - C H_{3}

C_{6} H_{5} \leftarrow C H_{2}

C_{6} H_{5} \leftarrow C H_{2} C H_{2}

C_{6} H_{5} \leftarrow C H \leftarrow C H_{3}

C_{6} H_{5} \leftarrow C (C H_{3})_{2}

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