Correct order of bond length among the following is:

C = O > C = C > C = N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C = O > C = N > C = C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C = C > C = N > C = O

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C = N > C = C > C = O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $C = C > C = N > C = O$
Bond length of $C = O$ is 120 pm. Bond length of $C = N$ is 129 pm. Bond length of $C = C$ is 134 pm. On moving from left to right in periodic table size of atom decreases. Therefore the correct order of bond length is $C = C > C = N > C = O$ . The correct option is $C$ .

Suggest Corrections

Similar questions

C - O, C - N, N - N

W h i c h o f f o l l o w i n g r e p r e s e n t β - h y d r o x y b u t y r a t e - c o - β - h y d r o x y v a l a r a t e ?

The van der waals radii of $O, N, C l, F$ and $N e$ increases in the order of:

I . H N = C = O \leftrightarrow H - O - C \equiv N

I I . ¯ N = C = O \leftrightarrow N \equiv C - O^{-}

I I I . C H_{3} - O | | C - ¯ C H_{2} \leftrightarrow C H_{3} -^{-} C = C H_{2}

I V . C H_{3} - O | | C - C H_{3} \leftrightarrow C H_{3} - O H | C = C H_{2}

Arrange F, Cl, O, and N in the decreasing order of electronegativity.

Join BYJU'S Learning Program