Correct order of electron affinity is:

F > C l > B r

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F > C l < B r

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C l > F > B r

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F < C l > B r

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Solution

The correct option is C $C l > F > B r$
Electronegativity $\propto$ Electron affinity
$∴$ The expected order should be $F > C l > B r$
But Fluorine has a small size with a small amount of space available in its $z p$ orbital. Because of this, new electron trying to attach to fluorine experience lower electron affinity from the electrons already living in the $z p$ orbital. While chlorine has much bigger size.
Therefore, correct electron affinity order is
$C l > F > B r$

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Similar questions

Among halogens, the correct order of amount of energy released in electron gain (electron gain enthalpy ) is
(a) F > Cl > Br > I (b) F < Cl < Br < I (c) F < Cl > Br > I (d) F < Cl < Br < I

Q. The decreasing order of electron affinity of

F, C l, B r i s F > C l > B r

Q. Arrange the following alkyl halides in decreasing order of the rate of

β

-elimination reaction with alcoholic KOH.

{C H}_{3} {C H}_{2} {C H}_{2} B r (i)

{C H}_{3} - C H {- C H}_{2} B r | {C H}_{3} (i i)

{C H}_{3} - {C H}_{2} - C H - {C H}_{3} | B r (i i i)

Q. The decreasing order of electron affinity of

F, C l,

and

B r

is:

Q. The correct order of polarizability is

I^{-}, B r^{-}, C l^{-}, F^{-}

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