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Standard XII

Chemistry

Periodicity

Correct order...

Question

Correct order of electronegativity of O, F, Cl and S is

O, F, Cl एवं S की विद्युतऋणता का सही क्रम है

O > F > Cl > S

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F > O > Cl > S

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F > Cl > O > S

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O > Cl > F > S

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Solution

The correct option is B F > O > Cl > S
Solution

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Similar questions

Given the standard reduction potentials:

Zn²⁺/Zn = - 0.74 V, Cl₂/Cl^- = 1.36 V, H⁺/1/2H₂ = 0 V and Fe³⁺/Fe²⁺ = 0.77 V.
The order of increasing strength as reducing agent is

Q. If internuclear distance between

C l

atoms in

C l_{2}

10

A & between

H

atoms in

H_{2}

is 2 A, then the internuclear distance between

H

C l

(Electronegativity of

H = 2.1

C l = 3.0)

is:

Q. Number of correct options among the following is/are:

(a) I^{-} > B r^{-} > C l^{-} > F^{-} (Polarizability)

(b) L i^{+} > N a^{+} > K^{+} > R b^{+} (Polarization power)

(c) H_{2} O > H_{2} S > H_{2} S e > H_{2} T e (Boiling point)

(d) H_{2}^{-} > H_{2}^{+} (order of stability)

Q. Consider the reaction:

{C l}_{2} (a q .) + H_{2} S (a q .) ⟶ S (s) + 2 H^{+} (a q .) + 2 {C l}^{-} (a q .)

The rate equation for this reaction is:
Rate

= k [{C l}_{2}] [H_{2} S]

Which of these mechanisms is/are consistent with this rate equation?

A

{C l}_{2} + H_{2} S ⟶ H^{+} + {C l}^{-} + {C l}^{+} + H S^{-}

(slow)

{C l}^{+} + H S^{-} ⟶ H^{+} + {C l}^{-} + S

(fast)

B

H_{2} S ⇌ H^{+} + H S^{-}

(fast equilibrium)

{C l}_{2} + H S^{-} ⟶ 2 {C l}^{-} + H^{+} + S

(slow)

Q. Consider the reaction :

C l_{2} (a q) + H_{2} S (a q) \to S (s) + 2 H^{+} (a q) + 2 C l^{-} (a q)

The rate equation for this reaction is

= k [C l_{2}] [H_{2} S]

Which of these mechanisms

i s / a r e

consistent with this rate equation?
(A)

C l_{2} + H_{2} S \to H^{+} + C l^{-} + C l^{+} + H S^{-}

(slow)

C l^{+} + H S^{-} \to H^{+} + C l^{-} + S

(fast)
(B)

H_{2} S \Leftrightarrow H^{+} + H S^{-}

(fast equilibrium)

C l_{2} + H S^{-} \to 2 C l^{-} + H^{+} + S

(slow)

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Correct order of electronegativity of O, F, Cl and S is O, F, Cl एवं S की विद्युतऋणता का सही क्रम है

The correct option is B F > O > Cl > SSolution

Correct order of electronegativity of O, F, Cl and S is

O, F, Cl एवं S की विद्युतऋणता का सही क्रम है

The correct option is B F > O > Cl > S
Solution