Correct order of ionisation energy are:
(I) $B e$ $>$ $B$
(II) $B e$ $>$ $C$
(III) $N$ $>$ $O$
(IV) $N$ $>$ $F$

I,III, IV

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I, II, III, IV

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I, III

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I, IV

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Solution

The correct option is A I, III
(e) $I ε = B e > B B e = 1 S^{2} 2 S^{2} B = 1 S^{2} 2 S^{2} 2 P^{1}$
$= N > 0$ $N = 1 S^{2} 2 S^{2} 2 P^{3}$ $O = 1 S^{2} 2 S^{2} 2 P^{4}$
$\Rightarrow$ depend on Most table
configuration of
electron

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Similar questions

Correct orders of first I.P. are -

(i) Li < B < Be < C

(ii) O < N < F

(iii) Be < N < Ne

Correct orders of Ist I.P. are -

(i) Li < B < Be < C

(ii) O < N < F

(iii) Be < N < Ne

The decreasing nucleophilic order of the following compound is:

$(i) Θ C H_{3}$

$(i i) Θ N H_{2}$

$(i i i) Θ O H$

$(i v) Θ F$

(I) H_{2} C = + N = - N

(I I) H_{2} + C - N = - N

(I I I) H_{2} - C - + N \equiv N

(I V) H_{2} - C - N = + N

Among the following structures I to IV
I. II. III. IV.
It is true that

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