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Electronic Configuration of d-Block Elements

Correct order...

Question

Correct order of oxidising agent, in $C r^{2 +}$ or $C u^{2 +}$ is:

C r^{2 +}

C u^{2 +}

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C r^{2 +}

C u^{2 +}

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C r^{2 +}

C u^{2 +}

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none of these

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Solution

The correct option is B $C r^{2 +}$ < $C u^{2 +}$
Option $(B)$ is correct.
$C u^{2 +}$ is better oxidising agent than $C r^{2 +}$ .
$C u^{2 +}$ has $[A r] 3 d^{9}$ configuration so it can easily gain electron to form stable $[A r] 3 d^{10}$ configuration. Hence it is oxidizing agent. On the other hand, $C r^{2 +}$ has $[A r] 3 d^{4}$ configuration so it can easily lose electron to form stable $[A r] 3 d^{3}$ configuration ( as it has half filled $t_{2 g}$ level). Hence it is reducing agent..

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Similar questions

Z n^{2 +}, N i^{2 +}, C u^{2 +} and C r^{2 +}

M^{2 +}

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{C r}_{2} O_{7}^{2 -} + C_{2} H_{4} O + H^{\oplus} ⟶ 2 {C r}^{3 +} + C_{2} H_{4} O_{2} + H_{2} O

{C u}_{2} O + H^{\oplus} + N O_{3}^{⊖} ⟶ {C u}^{2 +} + N O + H_{2} O

{C r}_{2} O_{7}^{2 -} + 2 ⊖ O H ⟶ 2 C r O_{4}^{2 -} + H_{2} O

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2 {C u}^{\oplus} ⟶ C u + {C u}^{2 +}

C r^{2 +}

M n^{3 +}

C r^{2 +}

M n^{3 +}

d^{4}

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