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Double Displacement Reaction

Correct order...

Question

Correct order of oxidising power of halogens is :

B r_{2} < C l_{2} < F_{2} < I_{2}

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F_{2} < I_{2} < B r_{2} < C l_{2}

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I_{2} < B r_{2} < C l_{2} < F_{2}

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I_{2} > B r_{2} > C l_{2} > F_{2}

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Solution

The correct option is C $I_{2} < B r_{2} < C l_{2} < F_{2}$
$2 I^{-} + {C l}_{2} ⟶ 2 {C l}^{-} + I_{2}$ .
Oxidising power is in the order: $I_{2} < {B r}_{2} < {C l}_{2} < F_{2}$ based on electrochemical series.

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Similar questions

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

(x^{2} + y^{2})

x

y

I_{2}, {B r}_{2}, {C l}_{2}, F_{2}

I_{2} < {B r}_{2} < {C l}_{2} < F_{2}

The correct order of the oxidizing power of Cl₂, Br₂, I₂ and O₂ is:

F_{2}, C l_{2}, B r_{2}, I_{2}

F_{2} > C l_{2} > B r_{2} > I_{2}

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