Question

Correct order of radius of the $1^{st}$ orbit of $H$, $H{e}^{+},L{i}^{2+},B{e}^{3+}$ is:

• A. $H>H{e}^{+}>L{i}^{2+}>B{e}^{3+}$
• B. $B{e}^{3+}>L{i}^{2+}>H{e}^{+}>H$
• C. $H{e}^{+}>B{e}^{3+}>L{i}^{2+}>H$
• D. $H{e}^{+}>H>L{i}^{2+}>B{e}^{3+}$

Answer 1

The correct option is A

$H>H{e}^{+}>L{i}^{2+}>B{e}^{3+}$

Radius $=\frac{0.529\times n^2}{Z}{A}^{\circ }$

n is same for all speices

$\Rightarrow r\propto \frac{1}{Z}$