Question

Correct set of four quantum numbers for the outermost electron of rubidium $(Z=37)$ is:

• A. $5,0,0,+\frac{1}{2}$
• B. $5,1,0,+\frac{1}{2}$
• C. $5,1,1,+\frac{1}{2}$
• D. $6,0,0,+\frac{1}{2}$

Answer 1

The correct option is A $5,0,0,+\frac{1}{2}$

Correct set of four quantum numbers for the outermost electron of rubidium ($Z=37$) is $5,0,0,+\frac{1}{2}$ or $n=5$, $l=0$, $m=0$ and $s=+\frac{1}{2}$

Rubidium $(Z=37)$ is an alkali metal in which the last electron enters 5s orbital.

For s orbital, $l=0$ and $m=0$.