Question

Correct set of four quantum numbers for valence electron of rubidium (Z = 37) is

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

Electronic configuration of $R{b}_{(}37)$ is

$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4s^{2}4p^{6}5s^1$

So for the valence shell electron $\left(5s^1\right)$

$n=5,l=0,m=0,s=+\frac{1}{2}$