Correct statement/s among the following are
A. Formaldehyde in presence of ConcNaOH gives methanol
B. Mesityl oxide has functional group of 'CHO'
C. Acetone hydrazone on treatment with KOH / CH₂OH - CH₂OH gives propane
D. Acetone has more boiling point than that of acetaldehyde

A, C only

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B,C only

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B,C,D only

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A,C,D only

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Solution

The correct option is D
A,C,D only

Mesityl oxide has keto group as functional group

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Similar questions

Choose the correct set of statement/s among the following:
A. Formaldehyde in presence of Conc NaOH gives methanol.
B. Mesityl oxide has a functional group of ‘CHO’.
C. Acetone hydrazine on treatment with KOH / CH2OH – CH2OH gives propane.
D. Acetone has more boiling point than of acetaldehyde.

Non planar molecules among the following

A) $B_{3} N_{3} H_{6}$ B) $B_{2} H_{6}$ C) $C_{2} H_{4}$ D) $C_{3} H_{6}$

Which of the following on hydrolysis can give methane

A) $A l_{4} C_{3}$ B) $B e_{2} C$ C) Ca $C_{2}$ D) $C H_{3} M g C l$

Q. Among the statements (a)-(d), the correct ones are :
a) Lithium has the highest hydration enthalpy among the alkali metals.
b) Lithium chloride is insoluble in pyridine.
c) Lithium cannot form ethynide upon its reaction with ethyne.
d) Both lithium and magnesium react slowly with

H_{2} O

$(C H_{3})_{3} C H K M n O_{4} - ---- \to A; C H_{3} (C H_{2})_{2} C H_{3} H C l - -- \to A l C l_{3} B; C H_{3} (C H_{2})_{4} C H_{3} C r_{2} O_{3}, 773 K - ------ \to 10 - 20 a t m C;$

Correct statements are

A. 'A' is tertiary alcohol B. 'B' contains a $3^{\circ}$ carbon

C. 'C' follows Huckel's rule D. both B and C are aromatic

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Correct statement/s among the following areA. Formaldehyde in presence of ConcNaOH gives methanolB. Mesityl oxide has functional group of 'CHO'C. Acetone hydrazone on treatment with KOH / CH2OH - CH2OH gives propaneD. Acetone has more boiling point than that of acetaldehyde

The correct option is D A,C,D onlyMesityl oxide has keto group as functional group

Correct statement/s among the following are
A. Formaldehyde in presence of ConcNaOH gives methanol
B. Mesityl oxide has functional group of 'CHO'
C. Acetone hydrazone on treatment with KOH / CH₂OH - CH₂OH gives propane
D. Acetone has more boiling point than that of acetaldehyde

The correct option is D
A,C,D only

Mesityl oxide has keto group as functional group