Question

Correct statement(s) regarding $As\left(C{H}_3\right)F_{2}C{l}_2$ molecule is/are:

• A. Maximum three halogen atoms can lie in same plane
• B. Both axial and equatorial plane have equal number of atoms
• C. $As-Cl$ bond length is longer than $As-F$ bond length
• D. Maximum five atoms can lie in equatorial plane

Answer 1

Answer: (A), (B), (C), (D)

The correct options are
A Maximum three halogen atoms can lie in same plane
B Both axial and equatorial plane have equal number of atoms
C $As-Cl$ bond length is longer than $As-F$ bond length
D Maximum five atoms can lie in equatorial plane

The geomtery of $As\left(C{H}_3\right)F_{2}C{l}_2$ according to bents rule is:
The $F$ (more electronegative atom) occupy axial position.
Now imagine this trigonal bipyramidal geomtery in 3-dimension.

(a) The plane which passes from $(C{l}_1,F_1,F_2,As)$ contains 3 - halogen atoms.

(b) Axial plane $\to$maximum atom = $5[F_1,F_2,As,C,H]$
equatorial plane $\to$ maximum atom = $5[C{l}_1,C{l}_2,As,C,H]$

(c) $(B.L.{)}_{As-Cl}>(B.L.{)}_{As-F}$
As size of $Cl$ - atom >> $F$ - atom.

(d) Equatorial plane $\to$ maximum atoms = $5[C{l}_1,C{l}_2,As,C,H]$
Hence, all options are correct.