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Phase and the General Equation

Corresponding...

Question

Corresponding to point A on acceleration time (a-t) curve of a particle executing SHM, there is a point 1 or 2 or 3 or 4 on velocity time (v-t) curve of the motion. The starting value of time on x-axis is different for two curves. Find the point:

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Solution

The correct option is D
4

Since the acceleration at any time 't' is basically just the value of the first derivative of the velocity at the same time 't', the slope of a v -t graph at a time 't' will tell you the acceleration at 't'.

The point A on the a-t graph represents a point of zero acceleration. On this v-t graph, it will correspond to a point where the slope is zero. Out of the points given,the v-t graph has zero slope only at 4.

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