Corresponding to point A on acceleration time (a-t) curve of a particle executing SHM, there is a point 1 or 2 or 3 or 4 on velocity time (v-t) curve of the motion. The starting value of time on x-axis is different for two curves. Find the point:
4
Since the acceleration at any time 't' is basically just the value of the first derivative of the velocity at the same time 't', the slope of a v -t graph at a time 't' will tell you the acceleration at 't'.
The point A on the a-t graph represents a point of zero acceleration. On this v-t graph, it will correspond to a point where the slope is zero. Out of the points given,the v-t graph has zero slope only at 4.