Question

${\cos }^{-1}\frac{1}{2}+2{\sin }^{-1}\frac{1}{2}$ is equal to-

• A. $\pi /4$
• B. $\pi /6$
• C. $\pi /3$
• D. $2\pi /3$

Answer 1

The correct option is D $2\pi /3$

${\cos }^{-1}\frac{1}{2}+2{\sin }^{-1}\frac{1}{2}=\frac{\pi }{3}+2\left(\frac{\pi }{6}\right)=\frac{\pi }{3}+\frac{\pi }{3}=\frac{2\pi }{3}$