Cos-112-2sin-112 is equal to -

The correct option is B 2π3 cos^ 1(12)=π3 ∴sin^ 1(12)=π2 π3=π6 ∴cos^ 1(12)+2sin^ 1(12)=π3+π3=2π3 . ...

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Domain and Range of Basic Inverse Trigonometric Functions

cos-112+2sin-...

Question

${cos}^{- 1} (\frac{1}{2}) + 2 {sin}^{- 1} (\frac{1}{2})$ is equal to :

\frac{π}{6}

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\frac{π}{3}

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\frac{2 π}{3}

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\frac{π}{4}

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{sin}^{- 1} \frac{1}{2} + {cos}^{- 1} \frac{1}{2} + {tan}^{- 1} \frac{1}{\sqrt{3}}

(a) \frac{2 π}{3} (b) \frac{π}{2}

(c) \frac{3 π}{4} (d) \frac{5 π}{6}

{cos}^{- 1} (\frac{1}{2}) + 2 {sin}^{- 1} (\frac{1}{2}) = \frac{2 π}{3}

{sin}^{- 1} (\frac{1}{2}) + {cos}^{- 1} (- \frac{1}{2})

\frac{π}{2}

{sin}^{- 1} (- \frac{1}{2}) + {cos}^{- 1} (\frac{1}{2})

\frac{π}{6}

{sin}^{- 1} (\frac{1}{2}) + {cos}^{- 1} (\frac{1}{2})

\frac{5 π}{6}

{sin}^{- 1} (1) + {cos}^{- 1} (- \frac{1}{2})

\frac{7 π}{6}

{sin}^{- 1} (1 - x) - 2 {sin}^{- 1} x = \frac{π}{2}

x

{sin}^{- 1} (1 - x) - 2 {sin}^{- 1} x = \frac{π}{2}

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