Cos -1 1 2 x 2 - 1- x 2 - 1- x 2 4 -cos -1 x 2 -cos -1 x holds for-

The correct option is A |x|≤ 1 clearly, x/2ϵ[ 1,1] amp; xϵ[ 1,1] #160; #160; #160; #160; #160;xϵ [ 2,2] amp; xϵ[ 1,1] I ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Vector Addition

cos -1 1 2 x ...

Question

${cos}^{- 1} {\frac{1}{2} x^{2} + \sqrt{1 - x^{2}} \sqrt{1 - \frac{x^{2}}{4}}} = {cos}^{- 1} \frac{x}{2} - {cos}^{- 1} x$ holds for:

| x | \leq 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x \in R

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0 \leq x \leq 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 1 \leq x \leq 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

{cos}^{- 1} {\frac{1}{2} x^{2} + \sqrt{1 - x^{2}} \sqrt{1 - \frac{x^{2}}{4}}} = {cos}^{- 1} \frac{x}{2} - {cos}^{- 1} x

{cos}^{- 1} {\frac{1}{2} x^{2} + \sqrt{1 - x^{2} .} \sqrt{1 - \frac{x^{2}}{4}}} = {cos}^{- 1} \frac{x}{2} - {cos}^{- 1} x

{cos}^{- 1} (\frac{1}{2} x^{2} + \sqrt{1 - x^{2}} \sqrt{1 - \frac{x^{2}}{4}}) = {cos}^{- 1} \frac{x}{2} - {cos}^{- 1} x

{sin}^{- 1} (\frac{2 x}{1 + x^{2}})

{cos}^{- 1} (\frac{1 - x^{2}}{1 + x^{2}})

1,

0 < x < 1

{sin}^{- 1} (\frac{2 x}{1 + x^{2}}) = {cos}^{- 1} (\frac{1 - x^{2}}{1 + x^{2}})

- 1 \leq x \leq 1

$l i m x \to 0 [\frac{l n c o s x}{\sqrt[4]{1 + x^{2}} - 1}] is equal to$

Join BYJU'S Learning Program