cos−1(12)+2 sin−1(12) is equal to
π/6
π/3
2π/3
π/4
cos−1(12)+2 sin−1(12)=π3+2.π6=π3+π3=2π3
cos−1(−12)−2sin−1(12)+3cos−1(−1√2)−4tan−1(−1) equals to