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Question

cos1(12)2sin1(12)+3cos1(12)4tan1(1) equals to


A

19π/12

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B

35π/12

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C

47π/12

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D

43π/12

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Solution

The correct option is D

43π/12


cos1(12)2sin1(12)+3cos1(12)4tan1(1)
=cos1(cos2π3)2sin1(sinπ6)+3cos1(cos3π4)4tan1tan(π4)
=2π32.π6+3.3π4+4.π4
=2π3π3+9π4+π
=8π4π+27π+12π12=43π12


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