Cos-1 15-7 -2tan-1 1-5 -

Cos^ 1 ( 15/7 )+tan^ 18/15 2tan^ 11/5=tan^ 15/12 ∴ cos^ 1 ( 15/17 )+2tan^ 1 ( 1/5 ) =tan^ 1 ( 8/15 )+tan^ 1 ( 5/12 ) tan^ 1 ( 8/15+5/12/1 40/180 )=tan^ 1 ( 17 ...

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Byju's Answer

Standard XIII

Mathematics

Basic Inverse Trigonometric Functions

cos-1 15/7 +2...

Question

$c o s^{- 1} (\frac{15}{7}) + 2 t a n^{- 1} (\frac{1}{5}) =$

\frac{π}{2}

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c o s^{- 1} (\frac{171}{221})

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\frac{π}{4}

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None of these

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Solution

The correct option is D None of these
$c o s^{- 1} (\frac{15}{7}) + t a n^{- 1} \frac{8}{15}$
$2 t a n^{- 1} \frac{1}{5} = t a n^{- 1} \frac{5}{12}$
$∴$ $c o s^{- 1} (\frac{15}{17}) + 2 t a n^{- 1} (\frac{1}{5})$
$= t a n^{- 1} (\frac{8}{15}) + t a n^{- 1} (\frac{5}{12})$
$t a n^{- 1} (\frac{\frac{8}{15} + \frac{5}{12}}{1 - \frac{40}{180}}) = t a n^{- 1} (\frac{171}{140}) = c o s^{- 1} (\frac{140}{221})$

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Similar questions

c o s^{- 1} (\frac{15}{7}) + 2 t a n^{- 1} (\frac{1}{5}) =

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, then

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cos−1(157)+2tan−1(15)=

The correct option is D None of thesecos−1(157)+tan−1815 2tan−115=tan−1512 ∴ cos−1(1517)+2tan−1(15) =tan−1(815)+tan−1(512) tan−1(815+5121−40180)=tan−1(171140)=cos−1(140221)

$c o s^{- 1} (\frac{15}{7}) + 2 t a n^{- 1} (\frac{1}{5}) =$