cos−1x{−cos(−13π6)} is equal to
−π6
5π6
π6
None
cos−1x{−cos(−13π6)} Use the result cos−1(−x)=π−cos−1x=π−cos−1(cos(13π6))=π−cos−1(cos(2π+π6))=π−cos−1(cos(π6))=π−π6=5π6