Cos -1 x -sin -1 x for- - -1 - x -1-2B- 0- x -1-2C- -1 - x -1-2 D- - x -1-2

The correct option is A 1 ≤ x lt; 1/√(2)cos^ 1x gt; sin^ 1x ⇒ sin^ 1x lt; π/4 ⇒ π/2≤ sin^ 1x ≤π/4⇒ 1 ≤ x lt; 1/√(2) ...

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Properties Derived from Trigonometric Identities

cos -1 x >sin...

Question

$c o s^{- 1} x > s i n^{- 1} x$ for:

0 < x < \frac{1}{\sqrt{2}}

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- 1 \leq x < \frac{1}{\sqrt{2}}

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- 1 \leq x \leq \frac{1}{\sqrt{2}}

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\leq x \leq \frac{1}{\sqrt{2}}

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Solution

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Similar questions

If $c o s^{- 1} x > s i n^{- 1}$ x then

{sin}^{- 1} x + {cos}^{- 1} x = \frac{π}{2}

| x | \leq 1

{s i n}^{- 1} x, {c o s}^{- 1} x, {t a n}^{- 1} x

{t a n}^{- 1} x + {t a n}^{- 1} y = {t a n}^{- 1} \frac{x + y}{1 - x y}

x y < 1

π + {t a n}^{- 1} \frac{x + y}{1 - x y}

x y > 1

{c o s}^{- 1} x + {c o s}^{- 1} [\frac{x}{2} + \frac{\sqrt{(3 - 3 x^{2})}}{2}]

(\frac{1}{2} \leq x \leq 1)

c o s (2 {c o s}^{- 1} x + {s i n}^{- 1} x)

x = 1 / 5

0 \leq {c o s}^{- 1} x \leq π

- π / 2 \leq {s i n}^{- 1} x \leq π / 2

x

{sin}^{- 1} x + {sin}^{- 1} (1 - x) = {cos}^{- 1} x

c o s^{- 1} x = 2 s i n^{- 1} \sqrt{\frac{1 - x}{2}} = 2 c o s^{- 1} \sqrt{\frac{1 + x}{2}}

s i n^{- 1} (- x) = - s i n^{- 1} x, c o s^{- 1} (- x) = π - c o s^{- 1} x (- 1 \leq x \leq 1)

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