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B
−1x≤1,x≠0
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C
0<x≤1
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D
−1≤x<0
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Solution
The correct option is C0<x≤1
Puttting θ=cos−1x in RHS, we have R.H.S =tan−1√1−x2x =tan−1√1−cos2θcosθ(0≤θ≤π) =tan−1sinθcosθ=tan−1tanθ =θ=cos−1x when −π2<θ<π2 i,e., when0≤θ≤π2 i.e., when 0<cosθ≤1 i.e., 0<x≤1