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Domain and Range of Basic Inverse Trigonometric Functions

cos 2θ1+tan 2...

Question

${cos}^{2} θ (1 + {tan}^{2} θ) = 1$

True

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False

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Solution

The correct option is A True
As we know that
${sec}^{2} A - {tan}^{2} A = 1$
${cos}^{2} θ (1 + {tan}^{2} θ) = {cos}^{2} θ \times {sec}^{2} θ$
$= {cos}^{2} θ \times \frac{1}{{cos}^{2} θ}$
$= 1$
So the relation is $True$

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