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Byju's Answer
Standard XII
Mathematics
Trigonometric Ratios of Multiple of an Angle
cos 2 x + a s...
Question
cos
2
x
+
a
sin
x
=
2
a
−
7
possesses a solution for
A
all value of a
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B
a > 6
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C
a < 2
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D
2
≤
a
≤
6
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Solution
The correct option is
D
2
≤
a
≤
6
cos
2
x
+
a
sin
x
=
2
a
−
7
1
−
2
sin
2
x
+
a
sin
x
=
2
a
−
7
⇒
sin
x
=
1
±
√
a
2
−
8
(
2
a
−
8
)
4
=
a
±
(
a
−
8
)
4
⇒
sin
x
=
a
−
4
2
,
2
(not possible)
Hence,
sin
x
=
a
−
4
2
Since,
−
1
≤
sin
x
≤
1
−
1
≤
a
−
4
2
≤
1
⇒
2
≤
a
≤
6
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0
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Q.
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