$c o s^{2} A + s i n^{2} A = 1$

True

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False

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Solution

The correct option is A True

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Similar questions

\frac{1 + sin 2 A - cos 2 A}{1 + sin 2 A + cos 2 A} = tan A

\frac{{sin}^{2} A}{{cos}^{2} A} + \frac{{cos}^{2} a}{{sin}^{2} A} = \frac{1}{{sin}^{2} A {cos}^{2} A} - 2

\frac{s i n^{2} A}{c o s^{2} A} + \frac{c o s^{2} A}{s i n^{2} A} = \frac{1}{s i n^{2} A c o s^{2} A} - 2

\frac{{sin}^{2} A}{{cos}^{2} A} + \frac{{cos}^{2} A}{{sin}^{2} A} = {sec}^{2} A c o s e c^{2} A - 2

$\frac{sin 2 A}{1 + cos 2 A}$ =

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