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Question

cos 4 x = cos 2x·

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Solution

Given that,

cos4x=cos2x cos4xcos2x=0( cosxcosy=2sin x+y 2 sin xy 2 ) 2sin3xsinx=0 sin3xsinx=0

So, either sin3x=0 or sinx=0.

General solution for sin3x=0,

3x=nπ x= nπ 3

Where, nz

General solution for sinx=0,

x=nπ

Where, nz

Thus, the general solutions are,

For sin3x=0,x= nπ 3

For sinx=0,x=nπ where, nz


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