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Complementary Trigonometric Ratios

cos 72o - sin...

Question

$cos 72^{o} - sin 18^{o} =$ ?

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Solution

We have $cos 72^{o} = cos (90^{0} - 18^{o}) = sin 18^{o}$
or, $cos 72^{o} - sin 18^{o} = 0$ .

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