Cos- - cos- 2 - sin- - sin- 2 reduces to-

( cosα #160; cosβ)^2 + ( sinα #160; sinβ)^2 cos ^2α #160; + cos ^2β #160; 2cosαcosβ #160; + sin ^2α #160; + sin ^2β #160; 2sinαs ...

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Equal Angles Subtend Equal Sides

cosα - cosβ 2...

Question

$(cos α - cos β)^{2} + (sin α - sin β)^{2}$ reduces to:

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Solution

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(cos α - cos β)^{2} + (sin α - sin β)^{2}

$(c o s α + c o s β)^{2} + (s i n α + s i n β)^{2}$ =

{(cos α + cos β)}^{2} + {(sin α + sin β)}^{2} = . . . . . . . . .

{(cos α - cos β)}^{2} + {(sin α - sin β)}^{2} = 4 {sin}^{2} {(α - β) / 2}

{(cos α + cos β)}^{2} + {(sin α + sin β)}^{2} = 4 {cos}^{2} (\frac{α - β}{2})

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