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Question

cosπ5cos2π5=14andcosπ5+cos3π5=12 without using standard value

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Solution

L.H.S=122sin(π/5)[sin22+π5]
L.H.S=14sin(π/5)sin[ππ5]=14 ....(1)
Also
cosπ5+cos3π5=2cosπ5cosπ5
=214=12...by (1)

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