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Question

cos(3π2+θ) =...............

A
- cos θ
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B
cos θ
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C
sin θ
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D
- sin θ
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Solution

The correct option is C sin θ
cos(3π2+θ)
=cos(π+(π2+θ)) since π+θ is in third quadrant cosine is negative.
=cos(π2+θ) since π2+θ is in second quadrant cosine is negative.
=sinθ

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