Cos-cos -1-1-7-sin -1-1-7-

The correct option is B 0cos{ cos^ 1 ( 1/7 )+sin^ 1 ( 1/7 ) }=cosπ/2=0 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Trigonometric Ratios of Compound Angles

cos[cos -1-1/...

Question

$c o s [c o s^{- 1} (\frac{- 1}{7}) + s i n^{- 1} (\frac{- 1}{7})] =$

\frac{- 1}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{4}{9}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

cos [{cos}^{- 1} (\frac{- 1}{7}) + {sin}^{- 1} (\frac{- 1}{7})] =

Given cot=7/8 then evaluate (1+sin)(1-sin)/(1+cos)(1-cos)

And (1+sin)/cos

{sin}^{- 1} (sin 5) + {cos}^{- 1} (cos 7) - {tan}^{- 1} (tan 5) =

c o t θ = \frac{7}{8}

\frac{(1 + s i n θ) (1 - s i n θ)}{(1 + c o s θ) (1 - c o s θ)}

If $cot θ = \frac{7}{8}$ , evaluate: $\frac{(1 + sin θ) (1 - sin θ)}{(1 + cos θ) (1 - cos θ)}$

Join BYJU'S Learning Program