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Question

cos[π2]θsin[e]θ= ?

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Solution

cos[π2]θsin[e]θ=

[π2]=[3.142]=[9.85]=9

[e]=[2.7]=2

cos[π2]θsin[e]θ=cos9θsin2θ

cos9θ+cos(π2+2θ)

2cos⎢ ⎢9θ+π2+2θ2⎥ ⎥cos⎢ ⎢9θ+π22θ2⎥ ⎥

2cos[π4+11θ2]cos[π47θ2]

cos[π2]θsin[e]θ=2cos[π4+11θ2]cos[π47θ2].

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