Cos- - cos 240- - - - cos 240- - - -

G.E = cosθ + 2cosθcos 240^∘ = 0, since cos 240^∘ = 1/2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sum of Trigonometric Ratios in Terms of Their Product

cosθ + cos 24...

Question

$cos θ + cos (240^{\circ} + θ) + cos (240^{\circ} - θ) =$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{3}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

cos (40 - θ) - sin (50 + θ) + \frac{{cos}^{2} 40 + {cos}^{2} 50}{{sin}^{2} 40 + {sin}^{2} 50}

c o s (40^{\circ} + θ) - s i n (50^{\circ} - θ) + \frac{c o s^{2} 40^{\circ} + c o s^{2} 50^{\circ}}{s i n^{2} 40^{\circ} + s i n^{2} 50^{\circ}}

$c o s 40^{\circ} + c o s 80^{\circ} + c o s 160^{\circ} + c o s 240^{\circ} =$

cos 24^{0} + cos 5^{0} + cos 175^{0} + cos 204^{0} + cos 300^{0} =

sin 120^{\circ} cos 150^{\circ} - cos 240^{\circ} sin 330^{\circ}

Join BYJU'S Learning Program