Question

$\cos \theta =\frac{3}{5}$ then $\frac{\sin \theta -\cot \theta }{2\tan \theta }=$

• A. $\frac{3}{160}$
• B. $\frac{7}{160}$
• C. $\frac{1}{160}$
• D. None of these

Answer 1

The correct option is A $\frac{3}{160}$

$\cos \theta =\frac{3}{5}$ then $\frac{\sin \theta -\cot \theta }{2\tan \theta }$

$\cos \theta =\frac{3}{5}$

$\sin \theta =\frac{4}{5}$

$\cot \theta =\frac{3}{4}$

$\tan \theta =\frac{4}{3}$

$\Rightarrow \frac{\frac{4}{5}-\frac{3}{4}}{2\times \frac{4}{3}}=\frac{\frac{16-15}{20}}{\frac{8}{3}}=\frac{1}{20}\times \frac{3}{8}$

$=\frac{3}{160}$.