$c o s θ = \frac{1}{2}$ then $θ$ is

2 n π \pm \frac{π}{6}

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n π \pm \frac{π}{2}

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2 n π \pm \frac{π}{3}

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n π

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Solution

The correct option is C $2 n π \pm \frac{π}{3}$
$cos θ = \frac{1}{2} \Rightarrow θ = 2 n π \pm \frac{π}{3}$

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