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Question

cos x14-cos2 x dx

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Solution

Let I=cos x 14-cos2xdx =cos x 14-1-sin2xdx =cos x sin2x-34dx =cos x sin2x-322dxPutting sin x=tcos x dx=dt I=1t2-322dt =12×32 ln t-32t+32+C =13 ln 2t-32t+3+C =13 ln 2 sin x-32 sin x+3+C t=sin x

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