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Question

(cos4θ − sin4θ)=?
(a) 1 − 2 sin2θ
(b) 1 − 2 cos2θ
(c) 2 − sin2θ
(d) 2 − cos2θ

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Solution

a) 1 − 2 sin2θ

(cos4θsin4θ)=(cos2θ)2(sin2θ)2=(cos2θ+sin2θ)(cos2θsin2θ)=1(1sin2θsin2θ)=12sin2θ

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