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Byju's Answer
Standard XII
Mathematics
Sum of Trigonometric Ratios in Terms of Their Product
cos 4 θ-cos 6...
Question
cos
4
θ
−
cos
6
θ
equals to
A
2
sin
5
θ
cos
θ
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B
−
2
sin
5
θ
sin
θ
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C
2
sin
θ
cos
5
θ
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D
2
sin
5
θ
sin
θ
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Solution
The correct option is
D
2
sin
5
θ
sin
θ
cos
4
θ
−
cos
6
θ
=
2
sin
(
4
θ
+
6
θ
2
)
sin
(
6
θ
−
4
θ
2
)
=
2
sin
5
θ
sin
θ
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Similar questions
Q.
2
(
s
i
n
6
θ
+
c
o
s
6
θ
)
−
3
(
s
i
n
4
θ
+
c
o
s
4
θ
)
is equal to _____.
Q.
(
sin
6
θ
+
cos
6
θ
)
−
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(
sin
4
θ
+
cos
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θ
)
+
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is equal to
Q.
lim
θ
→
0
1
−
cos
4
θ
1
−
cos
6
θ
Q.
2 (sin
6
θ + cos
6
θ) − 3 (sin
4
θ + cos
4
θ) is equal to
(a) 0
(b) 1
(c) −1
(d) None of these