Cost of a fertilizer is based on the percentage of nitrogen in it. Which of the fertilizers should be priced maximum?

N H_{4} N O_{3}

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N H_{2} C O N H_{2}

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K N O_{3}

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None of the above

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Solution

The correct option is B $N H_{2} C O N H_{2}$
Molecular weight of $N H_{4} N O_{3}$ is 80, $N H_{2} C O N H_{2}$ is 60, and $K N O_{3}$ is 101.

Percentage of $N$ in:

$N H_{4} N O_{3} = \frac{28 \times 100}{80} = 35 %$

$N H_{2} C O N H_{2} = \frac{28 \times 100}{60} = 46.7 %$
$K N O_{3} = \frac{14}{101} \times 100 = 13.9 %$

Urea, having the highest percentage of nitrogen, should have the highest cost.

Hence, option B is correct.

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Similar questions

The usefulness of a fertilizer depends upon percentage of nitrogen present in it. Find which of the following is a better fertilizer:
(a) ammonium nitrate [NH₄NO₃]
(b) ammonium phosphate [(NH₄)₃PO₄]
(N = 14, H = 1, O = 16, P = 31)

Calculate the percentage of Nitrogen in the fertilizer, Ammonium Nitrate $N H_{4} N O_{3}$

[H = 1, N = 14, O = 16]

Q. The nitrogen fertilizer with the highest percentage of nitrogen is:

Q. Which of the following fertilizers has the highest nitrogen percentage?

Q. Greenhouse gas, which can be emitted from storage of nitrogen based fertilizers, is:

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Cost of a fertilizer is based on the percentage of nitrogen in it. Which of the fertilizers should be priced maximum?

The correct option is B NH2CONH2Molecular weight of NH4NO3 is 80, NH2CONH2 is 60, and KNO3 is 101.Percentage of N in:NH4NO3=28×10080=35%NH2CONH2=28×10060=46.7% KNO3=14101×100=13.9% Urea, having the highest percentage of nitrogen, should have the highest cost.Hence, option B is correct.