Cost of identical articles is Rs. (2x + 3) and the cost of 10 similar articles is Rs. (4x - 5). Find the value of x.

Open in App

Solution

cost of 6 article $= (2 x + 3)$
cost of 1 article $= \frac{(2 x + 3)}{6}$ ................... (1)
cost of 10 article $= (4 x - 5)$
cost of 1 article $= \frac{(4 x - 5)}{10}$ ......................(2)
equating (1) and (2) we get
$\frac{(2 x + 3)}{6} = \frac{(4 x - 5)}{10}$
$10 (2 x + 3) = 6 (4 x - 5)$ cross multiplication
$\Rightarrow 20 x + 30 = 24 x - 30$
$\Rightarrow 4 x = 60$
$x = 15$

Suggest Corrections

Similar questions

Q. Cost of

24

identical articles is Rs

108

. Find the cost of

40

such articles.

Q. If the cost of a dozen identical articles is Rs.

672

, what will be the cost of

18

such articles?

The total cost price of a certain number of identical aricles is Rs.4,800. By selling the articles at Rs. 100 each. a profit equal to the cost price of 15 articles is made. Find the number of articles bought.

Q. 2x articles cost ₹(5x+54)and(x+2)similar article cost ₹(10x-4)find x

Q. The cost of

15

articles is Rs.

210

. What is the cost of

25

articles?

Join BYJU'S Learning Program

Cost of identical articles is Rs. (2x + 3) and the cost of 10 similar articles is Rs. (4x - 5). Find the value of x.

cost of 6 article =(2x+3)cost of 1 article =(2x+3)6 ................... (1) cost of 10 article =(4x−5)cost of 1 article=(4x−5)10 ......................(2) equating (1) and (2) we get (2x+3)6=(4x−5)10 10(2x+3)=6(4x−5)cross multiplication ⇒20x+30=24x−30 ⇒4x=60x=15