Question

Cost price of two motorcycles is same. One is sold at a profit of 15% and the other for Rs.4800 more than the first. If the net profit is 20%. Find the cost price of each motorcycle.

• A. Rs. 48000
• B. Rs. 52000
• C. Rs. 36000
• D. Rs. 42500

Answer 1

The correct option is A Rs. 48000

This problem can be solved by alligation method as,

Ratio is 1:1 as CP is same for both.
On solving, we get x = 25%.
Since, profit % is on CP,
$\therefore$ Difference in profit % of both the motorcycles
= 25% - 15% = 10% of CP of each motorcycle = 4800 (Given)
$\therefore$ CP of each motorcycle = Rs.48000

Conventional Approach:
Let the CP of each motorcycle be Rs. x, then
1.15x + 1.15x + 4800 = 1.2x + 1.2x
2(1.15x) + 4800 = 2(1.2x)
$\Rightarrow$ 0.x = 4800 $\Rightarrow$ x = 48000