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Question

cot1[(cosα)12]tan1[(cosα)12]=x, then sinx=

A
tan2(α2)
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B
cot2(α2)
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C
tan α
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D
cot(α2)
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Solution

The correct option is A tan2(α2)
tan1[1cosα]tan1[cosα]=x
tan11cosαcosα1+cosαcosα=xtan x=1cosα2cosα
sinx=1cosα1+cosα=2sin2α22cos2α2=tan2(α2).

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