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Question

cot 12 cot 38 cot 52 cot 60 cot 78=

A
23
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B
12
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C
13
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D
1
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Solution

The correct option is C 13
cot 12 cot 38 cot 52 cot 60 cot 78

=(cot 12.cot 78).(cot 38.cot 52).cot 60

={cot 12.cot(9012)}{cot 38.cot(9038)}.cot 60

=(cot 12.tan 12).(cot 38.tan 38).cot 60

[cot(90θ)=tan θ]

=1×1×13=13 [cot θ.tan θ=1 and cot 60=13]

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