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Question

cot2Acosec2Bcot2Bcosec2A=cot2Acot2B

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Solution

Simplifying the LHS of cot2Acsc2Bcot2Bcsc2A=cot2Acot2B.

cot2Acsc2Bcot2Bcsc2A=cot2A(1+cot2B)cot2B(1+cot2A)

=cot2A+cot2Acot2Bcot2Bcot2Acot2B

=cot2Acot2B

=RHS


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