Question

cot 53∘=

• A. $sin{65}^{\circ }$
• B. $tan{47}^{\circ }$
• C. $tan{37}^{\circ }$
• D. $cosec{37}^{\circ }$

Answer 1

The correct option is C $tan{37}^{\circ }$

We know that $cot\theta =tan({90}^{\circ }-\theta )$
$\therefore cot{53}^{\circ }=tan({90}^{\circ }-{53}^{\circ })=tan{37}^{\circ }$.