Question

$cot\theta$ can also be written as $tan({90}^{\circ }+\theta )$.

• A. True
• B. False

Answer 1

The correct option is B

False

$cot\theta =tan({90}^{\circ }-\theta )$.

Now, $tan({90}^{\circ }+\theta )=tan({90}^{\circ }-(-\theta \left)\right)$ = -$cot\left(\theta \right)$

And, -$cot\left(\theta \right)$ is not equal to $cot\left(\theta \right)$

$\therefore tan({90}^{\circ }+\theta )$ is not equal to $cot\left(\theta \right)$